(7x+4)(x^2-5x)=14

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Solution for (7x+4)(x^2-5x)=14 equation: 


Simplifying
(7x + 4)(x2 + -5x) = 14

Reorder the terms:
(4 + 7x)(x2 + -5x) = 14

Reorder the terms:
(4 + 7x)(-5x + x2) = 14

Multiply (4 + 7x) * (-5x + x2)
(4(-5x + x2) + 7x * (-5x + x2)) = 14
((-5x * 4 + x2 * 4) + 7x * (-5x + x2)) = 14
((-20x + 4x2) + 7x * (-5x + x2)) = 14
(-20x + 4x2 + (-5x * 7x + x2 * 7x)) = 14
(-20x + 4x2 + (-35x2 + 7x3)) = 14

Combine like terms: 4x2 + -35x2 = -31x2
(-20x + -31x2 + 7x3) = 14

Solving
-20x + -31x2 + 7x3 = 14

Solving for variable 'x'.

Reorder the terms:
-14 + -20x + -31x2 + 7x3 = 14 + -14

Combine like terms: 14 + -14 = 0
-14 + -20x + -31x2 + 7x3 = 0

The solution to this equation could not be determined.

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